March 2025

How to Factor Quadratics: A Step-by-Step Guide

Factoring a quadratic means rewriting it as a product of two binomials. For example, x² + 5x + 6 becomes (x + 2)(x + 3). This is useful for solving equations and simplifying expressions. Here's how to do it.

Form: x² + bx + c (leading coefficient = 1)

Find two numbers that multiply to c and add to b. Those numbers go in the binomials.

Example: Factor x² + 7x + 12

We need two numbers that multiply to 12 and add to 7.

x² + 7x + 12 = (x + 3)(x + 4)

Check: (x + 3)(x + 4) = x² + 4x + 3x + 12 = x² + 7x + 12 ✓

Example: Factor x² − 5x + 6

Two numbers that multiply to 6 and add to −5. Both must be negative.

x² − 5x + 6 = (x − 2)(x − 3)

Example: Factor x² + 2x − 15

Multiply to −15, add to 2. One positive, one negative.

x² + 2x − 15 = (x + 5)(x − 3)

Form: ax² + bx + c (leading coefficient ≠ 1)

Use the AC method (or "split the middle term"):

  1. Multiply a and c.
  2. Find two numbers that multiply to ac and add to b.
  3. Rewrite bx as the sum of those two terms.
  4. Factor by grouping.

Example: Factor 2x² + 7x + 3

a = 2, b = 7, c = 3. ac = 6. Need two numbers that multiply to 6 and add to 7 → 1 and 6.

2x² + 7x + 3
= 2x² + 1x + 6x + 3
= x(2x + 1) + 3(2x + 1)
= (2x + 1)(x + 3)

Check: (2x + 1)(x + 3) = 2x² + 6x + x + 3 = 2x² + 7x + 3 ✓

GCF First

Always check for a common factor before using other methods.

6x² + 12x + 6 = 6(x² + 2x + 1) = 6(x + 1)(x + 1) = 6(x + 1)²

Difference of Squares

a² − b² = (a + b)(a − b). Use when you have a perfect square minus another perfect square.

x² − 16 = x² − 4² = (x + 4)(x − 4)
9x² − 25 = (3x)² − 5² = (3x + 5)(3x − 5)

Solving Quadratic Equations by Factoring

Once factored, set each factor equal to zero and solve.

x² + 7x + 12 = 0
(x + 3)(x + 4) = 0
x + 3 = 0 → x = −3
x + 4 = 0 → x = −4

Solutions: x = −3 or x = −4

For quadratics that don't factor nicely, use the quadratic formula.

Common mistakes

Wrong signs: In x² − 5x + 6, both factors must be negative to get +6 and −5: (x − 2)(x − 3). Check by expanding.

Forgetting the leading coefficient: When a ≠ 1 (e.g., 2x² + 7x + 3), you can't just find factors of c. Use the AC method: multiply a × c, find factor pairs of that product, then split the middle term.

Practice problems

1. Factor: x² + 7x + 12

Show answer
(x + 3)(x + 4)

2. Factor: x² − 9

Show answer
(x + 3)(x − 3) — difference of squares

3. Factor: 2x² + 5x + 3

Show answer
(2x + 3)(x + 1)

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