Systems of Equations: Substitution and Elimination
A system of equations is two or more equations with the same variables. The solution is the (x, y) pair that satisfies both. For example, the lines y = 2x + 1 and y = −x + 4 intersect at one point — that point is the solution.
Method 1: Substitution
Solve one equation for one variable, then substitute that expression into the other equation.
Example:
2x + y = 7 (equation 2)
Equation 1 already gives y in terms of x. Substitute into equation 2:
4x + 1 = 7
4x = 6
x = 1.5
Now plug x = 1.5 into equation 1 to find y:
Solution: (1.5, 4)
Check: 2(1.5) + 4 = 3 + 4 = 7 ✓
When one variable is easy to isolate, substitution works well.
Method 2: Elimination (Addition)
Add or subtract the equations so one variable cancels out. You may need to multiply one or both equations first.
Example:
2x − y = 4 (2)
Subtract equation (2) from equation (1) to eliminate x:
2x + 3y − 2x + y = 8
4y = 8
y = 2
Plug y = 2 into (2): 2x − 2 = 4 → 2x = 6 → x = 3
Solution: (3, 2)
Example when you need to multiply first:
2x + 3y = 14 (2)
To eliminate x: multiply (1) by 2 and (2) by −3, then add.
−6x − 9y = −42
−5y = −10 → y = 2
Plug y = 2 into (1): 3x + 4 = 16 → 3x = 12 → x = 4
Solution: (4, 2)
Which Method to Use?
- Substitution — when one equation is already solved for a variable (e.g. y = 2x + 1)
- Elimination — when coefficients line up nicely or you can easily make them match
Special Cases
- No solution — parallel lines (same slope, different y-intercept)
- Infinitely many solutions — same line (equivalent equations)
Common mistakes
Dropping a negative: When multiplying an equation by a negative to eliminate a variable, every term must be multiplied — including the constant on the right side.
Forgetting to solve for both variables: After finding one variable, substitute back to find the other. The answer is a pair (x, y).
More examples
Example (substitution): y = 2x + 1 and 3x + y = 11
5x + 1 = 11
5x = 10
x = 2, y = 2(2) + 1 = 5
Solution: (2, 5)
Practice problems
1. Solve: x + y = 10 and x − y = 2
Show answer
2. Solve: y = 3x and 2x + y = 15