March 2025

Systems of Equations: Substitution and Elimination

A system of equations is two or more equations with the same variables. The solution is the (x, y) pair that satisfies both. For example, the lines y = 2x + 1 and y = −x + 4 intersect at one point — that point is the solution.

Method 1: Substitution

Solve one equation for one variable, then substitute that expression into the other equation.

Example:

y = 2x + 1    (equation 1)
2x + y = 7    (equation 2)

Equation 1 already gives y in terms of x. Substitute into equation 2:

2x + (2x + 1) = 7
4x + 1 = 7
4x = 6
x = 1.5

Now plug x = 1.5 into equation 1 to find y:

y = 2(1.5) + 1 = 3 + 1 = 4

Solution: (1.5, 4)

Check: 2(1.5) + 4 = 3 + 4 = 7 ✓

When one variable is easy to isolate, substitution works well.

Method 2: Elimination (Addition)

Add or subtract the equations so one variable cancels out. You may need to multiply one or both equations first.

Example:

2x + 3y = 12    (1)
2x − y = 4    (2)

Subtract equation (2) from equation (1) to eliminate x:

(2x + 3y) − (2x − y) = 12 − 4
2x + 3y − 2x + y = 8
4y = 8
y = 2

Plug y = 2 into (2): 2x − 2 = 4 → 2x = 6 → x = 3

Solution: (3, 2)

Example when you need to multiply first:

3x + 2y = 16    (1)
2x + 3y = 14    (2)

To eliminate x: multiply (1) by 2 and (2) by −3, then add.

6x + 4y = 32
−6x − 9y = −42
−5y = −10 → y = 2

Plug y = 2 into (1): 3x + 4 = 16 → 3x = 12 → x = 4

Solution: (4, 2)

Which Method to Use?

Special Cases

Common mistakes

Dropping a negative: When multiplying an equation by a negative to eliminate a variable, every term must be multiplied — including the constant on the right side.

Forgetting to solve for both variables: After finding one variable, substitute back to find the other. The answer is a pair (x, y).

More examples

Example (substitution): y = 2x + 1 and 3x + y = 11

Substitute: 3x + (2x + 1) = 11
5x + 1 = 11
5x = 10
x = 2, y = 2(2) + 1 = 5
Solution: (2, 5)

Practice problems

1. Solve: x + y = 10 and x − y = 2

Show answer
Add equations: 2x = 12, x = 6, y = 4. Solution: (6, 4)

2. Solve: y = 3x and 2x + y = 15

Show answer
2x + 3x = 15, 5x = 15, x = 3, y = 9. Solution: (3, 9)

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